Question

C) (a) Find the zeroes of the quadratic polynomial 18x²-2​

Answer 1

Answer:

$18 {x}^{2} - 2 \\ \\ = 2(9 {x}^{2} - 1) \\ \\ = 9 {x}^{2} - 1 \\ \\ = ({3x})^{2} - {(1)}^{2} \\ \\ = (3x + 1)(3x - 1) \\ \\ either \: 3x + 1 = 0 \\ \\ = > 3x = - 1 \\ \\ = > x = \frac{ - 1}{3} \\ \\ or \: 3x - 1 = 0 \\ \\ = > 3x = 1 \\ \\ = > x = \frac{1}{3}$

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Answer 2

Answer:

x=1/3 is the correct answer hope you get it