Question

c) A man divides 3(7x²+2x’y+4y) among his two sons. If one of them gets (5x+2y-4), how
much does the other one get?​

Answer 1

Answer:

The answer to the given question is the share that the other son gets is

$21 {x}^{2} + 6xy + 10y - 5x + 4$

Step-by-step explanation:

Given :

A man divides 3(7x²+2xy+4y) among his two sons.

one son gets 5x+2y-4

To find :

How much the other son gets?

Solution:

The total is 3(7x²+2xy+4y)

$3(7 {x}^{2} + 2xy + 4y)$

the one son gets

$5x + 2y - 4$

the sum that the other son gets is obtained by subtracting the one son's share from the total share. let us subtract the terms

$(3(7 {x}^{2} + 2xy + 4y)) - (5x + 2y - 4 )$

multiply the first term with the digit 3, and then the expression becomes.

$(21 {x}^{2} + 6xy + 12y) - (5x + 2y - 4)$

Removing the bracket from the second term,

$21 {x}^{2} + 6xy + 12y - 5x - 2y + 4$

Solving the like terms, we get the answer as

$2 1{x}^{2} + 6xy + 10y - 5x + 4$

The share that the other son gets is obtained as

$21 {x}^{2} + 6xy + 10y - 5x + 4$

Therefore, the final answer is found.

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