c)ABCD is a kite .angle BAC=30°,angle CBD=58°.find x,y and z.
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Given : ABCD is a kite
∠BAC=30° , ∠CBD=58°
To Find : x,y and z.
Solution:
ABCD is a kite
Diagonals of kite are perpendicular to each other
in Δ AOB
∠AOB = 90° , ∠BAO = 30° ∵ ∠BAO = ∠BAC
∠AOB + ∠BAC + ∠ABO = 180° ( sum of angles of Triangle)
=> 90° + 30° + x = 180°
=> x= 60°
in ΔBOC
58° + 90° + ∠BCO = 180°
=> ∠BCO = 32°
∠BCO = ∠DCO
=> 32° = y
y + z + 90° = 180°
=> z = 58°
x= 60°
y = 32°
z = 58°
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