Question

c)ABCD is a kite .angle BAC=30°,angle CBD=58°.find x,y and z.​

Answer 1

Step-by-step explanation:

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Answer 2

Given :   ABCD is a kite

∠BAC=30°   , ∠CBD=58°

To Find :  x,y and z.​

Solution:

ABCD is a kite

Diagonals of kite are perpendicular to each other

in Δ AOB

∠AOB = 90° , ∠BAO = 30°   ∵ ∠BAO = ∠BAC

∠AOB + ∠BAC + ∠ABO = 180°  ( sum of angles of Triangle)

=> 90° + 30° + x  = 180°

=>  x= 60°

in  ΔBOC

58°  + 90° + ∠BCO = 180°

=> ∠BCO = 32°

∠BCO =  ∠DCO  

=> 32° = y

y + z + 90° = 180°

=> z  = 58°

x= 60°

y = 32°

z = 58°

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