Question

c) an electric iron is rated 220v, 2kw. [4] (i) if the iron is used for 2h daily find the cost of running it for one week if it costs ` 4.25 per kwh. (ii) why is the fuse absolutely necessary in a power circuit?

Answer 1

electric iron = 2 kW
each work 2 hours daily
one day = 2×2 = 4 kW
consumption of seven days ( week )= 7×. 4 = 28 kW
cost for running it for one week = 28× 4.25=119 ₹ answer ......

. fuse works as a electrical bridge between power source and electronic equipment ......whenever there is excessive voltage fuse is the only device to detect it and prevent from damage ........

please mark it as brainliest.......

Answer 2

Explanation:

Power of the electric iron  P=2 kW

Power of the electric iron  P=2 kWTime for which the iron is operated daily  t=2 h

Power of the electric iron  P=2 kWTime for which the iron is operated daily  t=2 hDaily energy consumption  Edaily=Pt=2  kW×2 h=4 kWh

Power of the electric iron  P=2 kWTime for which the iron is operated daily  t=2 hDaily energy consumption  Edaily=Pt=2  kW×2 h=4 kWhTotal energy consumed in one week  Eweek=7×Edaily=7×4=28 kWh

Power of the electric iron  P=2 kWTime for which the iron is operated daily  t=2 hDaily energy consumption  Edaily=Pt=2  kW×2 h=4 kWhTotal energy consumed in one week  Eweek=7×Edaily=7×4=28 kWhTotal cost  =Rs.4.25×Eweek=Rs.4.25×28=Rs.119