Question

(c)
а
C
34. A body of mass 2 kg is placed on a horizontal fric-
tionless surface. It is connected to one end of a
spring whose force constant is 250 N/m. The other
end of the spring is joined with the wall. A particle of
mass 0.15 kg moving horizontally with speed v sticks
to the body after collision. If it compresses the spring
by 10cm, the velocity of the particle is
V
non M
*
m
(a) 3 m/s
(C) 10 m/s
(6) 5 m/s
(d) 15 m/s​

Answer 1

Answer:3 m/s

5 m/s

10 m/s

15 m/s

Answer :

D

Solution :

BY the conservation of momentum

m×v=(m+M)V

by the conservation of enrgy

12kx2=12(m+M)V2

=12(m+M)(mvm+M)2

⇒v=kx2(m+M)m2−−−−−−−−−−−√

=xmk(m+M)−−−−−−−−√

So v= 15 m/s

Explanation: