(c)
(e)
(f)
sin 2x + sin 4x + sin 6x=0
tan 0 + tan 20 + tan 30 = 0
sin 2x. tan x + 1 = sin 2x + tan x [H
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0
Answer:
(sin2x+sin6x)−sin4x=0
⇒2sin(
2
2x+6x
)cos(
2
2x−6x
)−sin4x=0
⇒2sin4xcos2x−sin4x=0
⇒sin4x(2cos2x−1)=0
⇒sin4x=0,2cos2x−1=0
⇒sin4x=0,cos2x=
2
1
∴4x=nπ,2x=2nπ±
3
π
∴x=
4
nπ
,nπ±
6
π
where n∈Z
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