Question

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Each side of a square is of length 4 units. The center of the square is (3,7) and one of its
diagonals is parallel to y = x. Find the coordinates of its vertices,
​

Answer 1

Step-by-step explanation:

R.E.F image

Let ABCD in square

AB=CD=DA=BC=?

P=(3,7)

draw PM⊥AB

M is mid point of AB

So, AM=MB=PM=?

diagonal is parallel to y = x, its sides

are parallel a to coordinate axis

∴ M = (3, 5)

⇒ A= (3 - 2, 5) = (1, 5)

B = (3 + 2 + 5) = (5, 5)

C = (3 + 5, 7 + 2) = (8, 9)

D = (3 - 2, 7 + 2) = (1, 9)

I hope this is help you..

Answer 2

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