Question

c) If percentage errors of measurement in velocity and mass are 2% and 4% respectively, what is the

percentage error in kinetic energy? ​

Answer 1

Answer:

Given percentage errors in mass and velocity = 2% and 3% respectively

The kinetic energy of the particle is given by

KE =

2

mv

2

The percentage error in kinetic energy will be

m

Δm

×100+2

v

Δv

×100

= 2+6

= 8%

Please mark as brilliant answer.........