Question

c) In the adjoining figure, AB-CD and LABC = LBCD. Prove that i) AC = BD
¡¡.)BE =CE​

Answer 1

Step-by-step explanation:

Step-by-step explanation:1. AC=BD

In triangle ABC and BCD

AB=CD(GIVEN) ANGLE ABC=ANGLE BCD

BC-BC(COMMON)

therefore trinagles are congruent by sas

So,AC=BD

2.in triangle AEB AND CED

BC-BC (COMMON)

ANGLE AEB-ANGLE CED(VERTICALLY OPPOSITE ANGLES)

AC-BD(FROM1.)

SO, subtracting BE FROM both sides

Therefore AE=DE

SO triangles ar congruent by sas

So,BE=CE