Question

(c) Infinite number of solutions.
Ajun thought of adding all the multiples of 5 he learnt in class. So would you help him to get the
answer to first 10 multiples of 5. According to you S10 =
(a) 275
(b) 500
(c) 50
(d) 550
​

Answer 1

Answer:

answer should be (a) ...

Answer 2

This Will Form An AP

AP : 5,10,15 ...

a = 5

d = 5

n = 10

sum fo first 10 terms of an AP

=> n/2 ( 2a + (n-1)d )

OR

=> n/2 (a + l )

we know l i.e last term = 50

ATQ :

=> 10/2 ( 5+50 )

=> 5(55)

5× 55 = 275