Question

C is a point on the line segment joining A(-3, 4) and
B (2, 1) such that AC = 2 BC then coordinates of Care
(c) (27)
(d) (7,2)​

Answer 1

Given

↗Coordinate of A ( -3,4 ) and coordinate of B(2,1)

↗AC = 2 BC

Solution

$\frac{bc}{ac} = \frac{1}{2}$

So, AC:BC = 2:1

Here we have to find coordinate of c let coordinate of c as ( x,y)

x1 = -3. x2 = 2

y1 = 4. y2. = 1

m1 = 2. m2 = 1

Now using internal divison formula , that is

Cx = x1m2 + x2m1 / m1 + m2

C(X) = -3(1)+2(2)/2+1

C(X) = -3+4/3

==>C(x) = 1/3

C(y) = y1m2 +y2m1/m1+m2

c(y) = 4(1)+1(2)/2+1

C(y) = 4+2 /3

==> C(y) = 2

So coordinate of C are ( 1/3 , 2 )

hope it helps