Computer Science, asked by Anonymous, 10 months ago

#C language program

Write a program , Input 2 matrix of 3×3 and display the multiplication of them .

#TheEnforceR​

Answers

Answered by upadhyayyash02
4

Answer:

#include <stdio.h>

void enterData(int first[][10], int second[][10], int r1, int c1, int r2, int c2);

void multiplyMatrices(int first[][10], int second[][10], int multResult[][10], int r1, int c1, int r2, int c2);

void display(int mult[][10], int r1, int c2);

int main() {

   int first[10][10], second[10][10], mult[10][10], r1, c1, r2, c2;

   printf("Enter rows and column for the first matrix: ");

   scanf("%d %d", &r1, &c1);

   printf("Enter rows and column for the second matrix: ");

   scanf("%d %d", &r2, &c2);

   while (c1 != r2) {

       printf("Error! Enter rows and columns again.\n");

       printf("Enter rows and columns for the first matrix: ");

       scanf("%d%d", &r1, &c1);

       printf("Enter rows and columns for the second matrix: ");

       scanf("%d%d", &r2, &c2);

   }

   enterData(first, second, r1, c1, r2, c2);

   multiplyMatrices(first, second, mult, r1, c1, r2, c2);

   display(mult, r1, c2);

   return 0;

}

void enterData(int first[][10], int second[][10], int r1, int c1, int r2, int c2) {

   printf("\nEnter elements of matrix 1:\n");

   for (int i = 0; i < r1; ++i) {

       for (int j = 0; j < c1; ++j) {

           printf("Enter a%d%d: ", i + 1, j + 1);

           scanf("%d", &first[i][j]);

       }

   }

   printf("\nEnter elements of matrix 2:\n");

   for (int i = 0; i < r2; ++i) {

       for (int j = 0; j < c2; ++j) {

           printf("Enter b%d%d: ", i + 1, j + 1);

           scanf("%d", &second[i][j]);

       }

   }

}

void multiplyMatrices(int first[][10], int second[][10], int mult[][10], int r1, int c1, int r2, int c2) {

   for (int i = 0; i < r1; ++i) {

       for (int j = 0; j < c2; ++j) {

           mult[i][j] = 0;

       }

   }

   for (int i = 0; i < r1; ++i) {

       for (int j = 0; j < c2; ++j) {

           for (int k = 0; k < c1; ++k) {

               mult[i][j] += first[i][k] * second[k][j];

           }

       }

   }

}

void display(int mult[][10], int r1, int c2) {

   printf("\nOutput Matrix:\n");

   for (int i = 0; i < r1; ++i) {

       for (int j = 0; j < c2; ++j) {

           printf("%d  ", mult[i][j]);

           if (j == c2 - 1)

               printf("\n");

       }

   }

}

Explanation:

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