C. Match the columns.
1. Sewing machine
a. Class III lever
2. See-saw
b. Class Il lever
3. Wheelbarrow
c. wedge
d. complex machine
4. Ice tongs
e. wheel-and-axle
5. Chisel
6. Screwdriver
f. Class I lever 2
2.4
g. screw
Answers
Answer:
1) sewing machine. - d) complex machine
2) see-saw - f) class I lever
3) wheelbarrow - b) class II lever
4) ice tongs - a) class III lever
5) chisel - c) wedge
6) screwdriver - e) wheel-and-axle
Explanation:
1. A complex machine is a machine made up of two or more simple machines that make your work easier to do. There are six simple machines from which all complex machines are made.
2. A Class 1 lever has the fulcrum placed between the effort and load. The movement of the load is in the opposite direction of the movement of the effort. This is the most common lever configuration.
3. A Class 2 lever has the load between the effort and the fulcrum. In this type of lever, the movement of the load is in the same direction as that of the effort.
4. A Class 3 lever has the effort between the load and the fulcrum. Both the effort and load are in the same direction.
5. A wedge is a triangular shaped tool, and is a portable inclined plane, and one of the six classical simple machines. It can be used to separate two objects or portions of an object, lift up an object, or hold an object in place.
6. The wheel and axle is a machine consisting of a wheel attached to a smaller axle so that these two parts rotate together in which a force is transferred from one to the other.
7. A screw is a mechanism that converts rotational motion to linear motion, and a torque to a linear force. It is one of the six classical simple machines. The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.
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Area of a square = Side × Side
Let the length of the side of the square be y.
==> y × y = 729cm²
==> y² = 729cm²
==> y = √729cm²
==> y = 27cm
Therefore, the length of one side of a square whose area is 729cm² is 27cm.
.
Perimeter of a square = 4 × Side
Let the unknown side of the square be z.
==> 4 × z = 20cm
==> z = 20cm/4
==> z = 5cm
Therefore, the side of the square whose perimeter is 20cm is 5cm.
Area of a square = Side × Side
==> ( 5cm ) × ( 5cm )
==> 25cm²
Therefore, the area of the square whose perimeter is 20cm.
.
Area of a square = Side × Side
Let the unknown side of the square be x.
==> x × x = 81cm²
==> x² = 81cm²
==> x = √81cm²
==> x = 9cm
Therefore, the side of the square whose area is 81cm² is 9cm.
Perimeter of a square = 4 × Side
==> 4 × ( 9cm )
==> 36cm
Therefore, the perimeter of the square whose area is 81cm² is 36cm.
.
Side of the square field = 35m
We have to find the perimeter of the square field because it is given that the man walks around it !
Perimeter of a square = 4 × Side
==> 4 × ( 35m )
==> 140m
Man walks around it for 3 times :
==> 140m × 3
==> 420m
Therefore, the man walks 420m.
.
It is given that he crossed twice, so :
==> 48m/2 = 24m
It is said that he crossed around a square field, so it is the perimeter (24m) of the square field.
Perimeter of a square = 4 × Side
Let the unknown side of the square be g.
==> 4 × g = 24m
==> g = 24m/4
==> g = 6m
Therefore, the side of the square field is 6m.
The square field is supposed to be fenced at the rate of Rs.1.75 per m, So :
==> Perimeter × Rs.1.75
==> 24m × Rs.1.75
==> Rs.42
Therefore, the cost of fencing the field at the rate of Rs.1.75 per m is Rs.42.
is
Given, length = 10m ; breadth = 8m
Area of a rectangle = length × breadth
==> ( 10m ) × ( 8m )
==> 80m²
It costs Rs.18 to carpet 1m², to carpet 80m², the cost is :
==> Area × Rs.18
==> 80m² × Rs.18
==> Rs.1440
Therefore, Rs.1440 is the cost for carpeting 80m² is Rs.1440.
.
1km = 1000m
==> length = 10,000m
Area of a rectangle = length × breadth
==> ( 10,000m ) × ( 3m )
==> 30,000m²
Cost for 30,000m² is :
==> Area × Rs.2.50
==> 30,000m² × Rs.2.50
==> Rs.75,000
Therefore, the total cost to prepare a road of area 30,000m² is Rs.75,000
.
Let the unknown length of the rectangle be k.
Area of a rectangle = length × breadth
==> k × 20m = 800m²
==> k = 800m²/20m
==> k = 40m
Therefore, the length is 40m.
Since, it is to be fenced, we have to find out the perimeter of the rectangle :
Perimeter of a rectangle = 2 ( length + breadth )
==> 2 ( 40m + 20m )
==> 2 ( 60m )
==> 120m
Total cost to fence 120m at the rate of Rs.1.80 per m :
==> Perimeter × Rs.1.80
==> 120m × Rs.1.80
==> Rs.216
Therefore, the cost to fence the rectangular garden is Rs.216.
.
Area of a square = Side × Side = 6400m²
Let the unknown side of the square be c.
==> c × c = 6400m²
==> c² = 6400m²
==> c = √6400m²
==> c = 80m
The plot is to be fenced, so we have to find the perimeter.
Perimeter of a square = 4 × Side
==> 4 × ( 80m )
==> 320m
Therefore, the perimeter is 320m.
Total cost to fence 320m at the rate of Rs.1.50 per m :
==> Perimeter × Rs.1.50
==> 320m × Rs.1.50
==> Rs.480
Therefore, the total cost is Rs.480 to fence the square plot.
.