Question

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In the adjoining figure, ABCD is a rectangle of size
18 cm by 10 cm In ABEC, ZE = 90° and EC = 8 cm.
Find the area enclosed by the pentagon ABECD.
(Hint. From AEBC, EB2 = 102 – 82. Area of pentagon
-- area of rectangle ABCD - area of AEBC.]
B
18 am​

Answer 1

Answer:

math are science of counting

Answer 2

Answer:

In △BCE

⇒EB

2

+EC

2

=BC

2

⇒EB

2

=BC

2

−EC

2

⇒EB=

100−64

=

36

=6cm

Area of the △EBC=

2

1

×EB×EC

=

2

1

×6cm×8cm=24cm

2

Area of rectangle ABCD=18cm×10cm=180cm

2

Area(shaded region) =ar(rectangle)−ar(△BCE)

180cm

2

−24cm

2

=156cm

2