.C+O2 → CO2, Consider 3g of C reacts with 16g of O2 then find Limiting reagent
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Answer:
C(s) + O
2
→CO
2
(g)
No. of moles of carbon =
12
36
=3 moles
No. of moles of oxygen =
32
32
=1 moles
So, 2 moles of carbon is left and oxygen will be completed.
So, O
2
is limiting reagent.
Explanation:
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