Question

(c) On A PQR
23. Find the largest and the smallest digit in the blank space of the
given number. so that the number is divisible by 3.
solution ​

Answer 1

Answer:

Answer is 86724

Step-by-step explanation:

_6724.

The number is divisible by 3 if the sum of its digits is divisible by 3.

Adding the digits of the given number,

6+7+2+4=19

If 2 is added to the above number then the number will become 21 which is divisible by 3 and also, 2 is the smallest number that can fill the missing space.

Now, if 8 is added to the given number then the number will become 27 which is divisible by 3 and 8 is largest number that can make the given number divisible by 3.

Therefore, the smallest number will be 2 which will form 26724 and the largest number will be 8 forming 86724.