Question

C++ program for sum of all integers between 100 and 9000 and are divisible by 7

Answer 1

Answer:

Program to find sum of all integers between 100 to 9000 and are divisible by 7 in c

Answer:

5783050.

Step-by-step explanation:

= 5783050.

Hence, the sum of all integers between 100 to 9000 and are divisible by 7 is 5783050.

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Answer 2

Explanation:

IAnswer:

5783050

Step-by-step explanation:

Since, integers between 100 to 9000 that are divisible by 7,

105, 112, 119, .......... 8995,

Which is an AP,

Having first term, a = 105,

d = 7,

Last term, l = 8995

Let n be the total number of terms,

\implies a + (n-1)d = l⟹a+(n−1)d=l

105 + (n - 1)7 = 8995105+(n−1)7=8995

7(n-1) = 88907(n−1)=8890

n - 1 = 1270n−1=1270

\implies n = 1271⟹n=1271

Hence, the sum of the above AP,

S_{1271}=\frac{1271}{2}(2(105)+(1271-1)7)S

1271

=

2

1271

(2(105)+(1271−1)7)

=\frac{1271}{2}(210+1270(7))=

2

1271

(210+1270(7))

=\frac{1271}{2}(9100)=

2

1271

(9100)

=1271\times 4550=1271×4550

= 5783050

Hence, the sum of all integers between 100 to 9000 and are divisible by 7 is 5783050.