C program to find gcd of two numbers using recursion
Answers
input:
#include <stdio.h>
int hcf(int n1, int n2);
int main()
{
int n1, n2;
printf("Enter two positive integers: ");
scanf("%d %d", &n1, &n2);
printf("G.C.D of %d and %d is %d.", n1, n2, hcf(n1,n2));
return 0;
}
int hcf(int n1, int n2)
{
if (n2 != 0)
return hcf(n2, n1%n2);
else
return n1;
}
Output:Enter two positive integers: 366
Enter two positive integers: 36660
Enter two positive integers: 36660G.C.D of 366 and 60 is 6.
Answer:
#include <stdio.h>
int hcf(int n1, int n2);
int main() {
int n1, n2;
printf("Enter two positive integers: ");
scanf("%d %d", &n1, &n2);
printf("G.C.D of %d and %d is %d.", n1, n2, hcf(n1, n2));
return 0;
}
int hcf(int n1, int n2) {
if (n2 != 0)
return hcf(n2, n1 % n2);
else
return n1;
}
Explanation: