C' program to swap the alternate digits of the given number
Answers
Answered by
21
#include<stdio.h>
#include<conio.h>
void main()
{
int array[10],i;
printf("Enter the elements:");
for(i=0;i<10;i+=2)
scanf("%d",&array[i]);
printf("Alternate elements of a given array:");
for(i=0;i<10;i+=2)
printf("%d\n",array[i]);
}
#include<conio.h>
void main()
{
int array[10],i;
printf("Enter the elements:");
for(i=0;i<10;i+=2)
scanf("%d",&array[i]);
printf("Alternate elements of a given array:");
for(i=0;i<10;i+=2)
printf("%d\n",array[i]);
}
Answered by
4
#include <stdio.h>
#include <conio.h>
#include <string.h>
void main(){
char str[20],tmp;
int i,j;
clrscr();
printf("\nEnter a string : ");
scanf("%s",str);
printf("\n\nOriginal String : %s",str);
for(i=0;i<strlen(str);i=i+2){
tmp = str[i];
str[i] = str[i+1];
str[i+1] = tmp;
}
printf("\nAfter Swap String : %s",str);
getch();
}
Similar questions