Question

c+r=10
d+r=20
d+c=24
d+r+c=?​

Answer 1

Given c + r = 10 --(1)

d + r = 20 ---(2)

d + c = 24 ---(3)

/* Subtract Equation (1) from Equation (2) ,we get */

d - c = 10 ---(4)

/* Add Equations ( 3) and (4), we get */

=> 2d = 34

=> d = 17

/* Put d Value in equation (2) , we get */

17 + r = 20

=> r = 3

Therefore.,

$Value \: of \: d + r + c \\= (d+c) + r \\= 24 + 3 \\= 27$

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