(c)
Rewrite the following code fragment without break and continue :
while(Ch!= '*')
{ if(Ch == '?')
break;
if(Ch!= '\n')
continue;
a++; }
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6
Answer:
Explanation:
there : while(Ch!='*')
{ if(Ch=='?')
Ch='*';
if(Ch!='\n')
goto there;
a++;
}
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