Question

c) Show that tan 75° + cot 75º = 4.​

Answer 1

Answer:

tan 75° = tan(45+30) = tan 45 + tan 30 / 1-tan 45 tan 30 = 1+1/√3 / 1-1/√3 = √3+1/√3-1 = (√3+1)^2/2 = 4+2√3/2 = 2+√3

Now, cot75 = 1/tan 75 = 1/2+√3 = 2-√3/4-3 = 2-√3

So, tan75 + cot 75 = 2+√3 + 2-√3 = 4 !!

Hope this helps you !

Answer 2

Answer:

using tan (a+b) concept we can easily solve this