c++ swap program write
Answers
Answered by
2
hey there,
There are 3 methods of writing c++ swap programme one is using temporary variables and the other is without using temporary variables and other is using third variable.
Here I am writing program with non temporary variables
let's begin
#include <iostream>
using namespace std;
int main( )
{
int a = 5, b = 10;
cout << "Before swapping." << endl;
cout << "a = " << a << ", b = " << b << endl;
a = a + b;
b = a - b;
a = a - b;
cout << "\nAfter swapping." << endl;
cout << "a = " << a << ", b = " << b << endl;
return 0;
}
There are 3 methods of writing c++ swap programme one is using temporary variables and the other is without using temporary variables and other is using third variable.
Here I am writing program with non temporary variables
let's begin
#include <iostream>
using namespace std;
int main( )
{
int a = 5, b = 10;
cout << "Before swapping." << endl;
cout << "a = " << a << ", b = " << b << endl;
a = a + b;
b = a - b;
a = a - b;
cout << "\nAfter swapping." << endl;
cout << "a = " << a << ", b = " << b << endl;
return 0;
}
Answered by
8
ANSWER
.................
THE PROGRAM IS GIVEN BELOW
.................
#include
<iostream>
by using namespace std;
int main( )
{
int a = 5,
b = 10;
cout
<< "Before swapping." << endl;
cout << "a = " << a << ", b = "
<< b << endl;
a = a + b;
b = a - b;
a = a - b;
cout << "\nAfter swapping." << endl;
cout << "a = " << a << ", b = " << b << endl;
return 0;
}
.................
THE PROGRAM IS GIVEN BELOW
.................
#include
<iostream>
by using namespace std;
int main( )
{
int a = 5,
b = 10;
cout
<< "Before swapping." << endl;
cout << "a = " << a << ", b = "
<< b << endl;
a = a + b;
b = a - b;
a = a - b;
cout << "\nAfter swapping." << endl;
cout << "a = " << a << ", b = " << b << endl;
return 0;
}
Similar questions