Question

Calculate the volume of ammonia produced at stp when 140g of nitrogen gas reacts

Answer 1

N₂ + 3H₂ → 2NH₃

140g of nitrogen gas = 140/28 = 5 mol

At STP
1 mol of nitrogen gas produces 2 × 22.4L of ammonia
5 mol of nitrogen gas will produce 10 × 22.4L of ammonia

Volume of ammonia gas produced is 224L

Answer 2

Given'
Mass = 140 g
= 140/28
= 5 mol

Now'
1 mol of nitrogen = 2 × 22.4 L ammonia
5 mol of nitrogen = 10 × 22.4 L ammonia

Volume of ammonia = 10 × 22.4 L
= 224 L