C takes 6 days to complete 1/2 of a work D takes 5 days to complete 1/3 of the same work they take turn to complete the task, if C works for the first 4 days, in how many days will D complete the rest of the work without the help of C
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C takes 6 days = 1/2 work
D takes 5 days = 1/3 work
If C works for 4 days in how many days D will complete the work
From the above C takes 12 days to complete the work
And D takes 15 days to complete the work
So per day work of C = 1/12
And per day work of D = 1/15
So, the work of C for 4 days = 1/12 * 4
C for 4 days = 1/3 of the work
Remain work = 1- 1/3= 2/3 of the work
How many days D will takes to complete the remain work which is 2/3
Days of D = 2/3= 2(1/3) = 2(5 days of D= 1/3 work)
So, days of D = 2(5)= 10 days
So, D will takes 10 days to complete the remain work which is 2/3
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