(c) the filament of an electric lamp, which draws a current of 0.25 a is used for four hours. Calculate the amount of charge flowing through the circuit.
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Answered by
7
given, I=.25A
t=4hr=4*60*60 sec
q=I*t
q=60*60=3600 C
Answered by
2
Answer:
As Amount of charge =Current *time
Q=IT
Where, I=0.25A
T=4hours
=3600sec
The amount of charge=0.25A*3600
=3600Coulomb
Charge=3600C
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