Math, asked by njemarose7, 3 days ago

(c) The potential for the HOH bond angle in a water molecule can be represented by the following expression: V(6HOH) Кнон (Өнон — Ө)2 %3| where KHOH = 0.1103 kJ mol-degree-2. A starting structure of the water molecule, with C2v symmetry, has an angle = 110.0°, and the first derivative of the potential with respect to this angle has Өнон the...

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Answered by Anonymous

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again and I don't know maths science waiting

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