Question

c. Two buildings are 45m apart. With what velocity must a ball
be thrown horizontally from a window 50m above the ground
in one building so that it enters a window 5.9m above the
ground in the other building?​

Answer 1

Answer:

Difference in height = s = 145 - 22.5 = 122.5 m

From Newton's Equations of motion we know that:

s = ut +1/2 at²s = ut + \frac{a t^{2} }{2}s=ut+2at2  ...(i)

Using it along the vertical direction , we get

=\ \textgreater \ 122.5 = \frac{g t^{2} }{2}= \textgreater 122.5=2gt2 ...(ii)

Using (i) in the horizontal direction we get:

40 = u t

=> t = \frac{40}{u}t=u40 ...(iii)

Solving equation (ii) and (iii), we get:

u = 8 m/s