Math, asked by Arya6644, 8 months ago

c)
U
14 is divisible by 111
A doorway is decorated as shown in the given figure the
semicircle is oflength 84cm The centres of 3 equals
ABC is an isosceles triangle with AB-AC if BO-O
wn in the given figure. There are four semi circles BC, the diameter of the larger
The centres of 3 equal semi circles lie on BC and they have radius 14cm each
31
the shaded region.
AB-AC if BO=OC, find the
(Use T = 22
2x42842​

Answers

Answered by amitnrw
0

1932 cm²   is the area of the shaded region

Step-by-step explanation:

Diameter of Larger Semicircle = 84 cm

Radius = 84/2 = 42 cm

Area of Larger Semi circle = (1/2) π * (42)²

π  = 22/7

= (1/2) (22/7) * 42²

= 2772 cm²

Radius of Small circle = 42/3 = 14 cm

Area of 3 Small Semi circle =  3 (1/2) (22/7) * (14)²

= 924 cm²

ABC is an isosceles triangle with AB = AC

=> AO ⊥ BC

AO = 42 cm radius

Area of Δ ABC = (1/2) * 84 * 42

= 1764 cm²

area of the shaded region = Area of Larger Semi circle + Area of 3 Small Semi circle - Area of Δ ABC

=  2772 + 924 - 1764

=  1932 cm²  

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