Question

C varies directly as the square of d, if cis 14 and d is 64, find c when d is 256

Answer 1

Answer:

Step-by-step explanation:

Then c will be 28 . .

Hope its true and helps u . . .

Answer 2

Answer:

The value of c when d is 256 = 224

Step-by-step explanation:

Given

c varies directly as the square of d

c is 14 and d is 64

To find,

c when d is 256

Solution:

Since c varies directly as the square of d, we have

c is directly proportional to  d²

c∝d²

c = kd², where k is constant

$\frac{c}{d^2} = k$

Also given,  c is 14 and d is 64

$k = \frac{14}{64^2}$ -----------(1)

Again, when d  = 256

k = $\frac{c}{256^2}$ ------------(2)

Equating the value of k in equations(1) and (2) we get

$\frac{14}{64^2} = \frac{c}{256^2}$

c= $\frac{14X256^2}{64^2}$ = 14×16

c = 224

The value of c when d is 256 = 224

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