Question

C. When a gas is heated the particles move
more quickly. What is the change in
volume of a heated gas if the pressure
is kept constant ?​

Answer 1

Answer:

$V_{2} = V_{1} *(\frac{T_{2}}{T{1}})$

change in volume =  $(\frac{T_{2}}{T_{1}} - 1) *V_{1}$

Explanation:

PV = mRT

so initially

$P_{1}V_{1} = mRT_{1}$

after heating

$P_{2}V_{2} = mRT_{2}$

divide these two equations we get

$\frac{P_{1}V_{1}}{P_{2}V_{2}}$ = $\frac{mRT_{1}}{mRT_{2}}$

since pressure is constant P1=P2

so

the final volume will be

$V_{2} = V_{1} *(\frac{T_{2}}{T{1}})$

Temperature must be in Kelvin

Change in volume = (v2-v1) = v1*t2/t1 -v1

                               $(\frac{T_{2}}{T_{1}} - 1) *V_{1}$

Answer 2

Answer:

v2 = v1 * t2/t1

Explanation: