Question

two pipes can fill a tank in 10 and 20 hours respectively there is a leakage at the bottom of the tank which takes 40 hours to empty the tank if both pipes are usee together then how long it will take to fill the tank​

Answer 1

Answer:

total time taken to fill the tank = 8 hours

Step-by-step explanation:

in 1 hour

part of tank filled by 1st pipe= 1/10

2nd pipe = 1/20

part of tank empty by leakage= 1/40

part of tank filled in 1 hr =

$\frac{1}{10} + \frac{1}{20} - \frac{1}{40}$

$= \frac{4 + 2 - 1}{40}$

$= \frac{5}{40}$

$= \frac{1}{8}$

total time taken to fill the tank = 8 hours

Answer 2

Answer:

8 hours

Step-by-step explanation:

1/10+1/20-1/4

4+2-1/40

5/40

1/8

hence ,the answer is 8 hours