(c) Write the first natural number term of the arithmetic sequence 14/8,17/8,20/8
Answers
Answered by
19
Answer:
23/8
Step-by-step explanation:
14/8 + 3/8 = 17/8
17/8 + 3/8 = 20/8
20/8 + 3/8 = 23/8
Answered by
0
The first natural number term of the given arithmetic sequence is 4.
Given: The sequence 14/8, 17/8, 20/8, ...
To find: The first natural number term of the arithmetic sequence
Solution:
AP = 14/8, 17/8, 20/8, ...
Let the first term = a
common difference = d
nth term = tₙ
As we can see,
a = 14/8
d = 17/8 - 14/8 = 3/8
tₙ = a + (n - 1)d
⇒ tₙ = 14/8 + (n - 1)(3/8)
∴ Continuing the series, we get
AP = 14/8, 17/8, 20/8, 23/8, 26/8, 29/8, 32/8
⇒ AP = 14/8, 17/8, 20/8, 23/8, 26/8, 29/8, 4 [since 32/8 = 4]
⇒ 4 is the first natural number term of the arithmetic sequence.
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