Question

c2−3+6d\dfrac c2-3+\dfrac 6d2c​−3+d6​start fraction, c, divided by, 2, end fraction, minus, 3, plus, start fraction, 6, divided by, d, end fraction when c=14c=14c=14c, equals, 14 and d=3d=3d=3d, equals, 3.

Answer 1

Answer:

hey mate ✌✌

if the fraction c=14c=14c=14c

d=3d=3d=3d.

Answer 2

Answer:

$Evaluation is \frac{c}{2}-3+\frac{6}{d}=6$

Step-by-step explanation:

Given :

$Expression \: \frac{c}{2}-3+\frac{6}{d}$

when c=14 and d=3.

To find : Evaluate the expression ?

Solution :

$Expression \frac{c}{2}-3+\frac{6}{d} \:$

Substitute c=14 and d=3,

$</p><p>\frac{c}{2}-3+\frac{6}{d}=\frac{14}{2}-3+\frac{6}{3} </p><p>$

$\frac{c}{2}-3+\frac{6}{d}=7-3+2$

$\frac{c}{2}-3+\frac{6}{d}=6$

$Therefore, \: evaluation \: is \frac{c}{2}-3+\frac{6}{d}=6$