Chemistry, asked by kruthikaR96, 19 days ago

C2h5i and c3h7i react with sodium metal to give

Answers

Answered by indrajs2007
0

Answer:

Explanation:

Correct option is

D

Butane + Pentane + Hexane

In Wurtz reaction, if two different alkyl halides are treated with sodium metal in presence of dry ether then a mixture of three different products is obtained.

Thus, when a mixture of 1-iodoethane and 1-iodopropane is treated with sodium metal and dry ether, butane, pentane, and hexane will be obtained.

1−iodoethane

CH  

3

CH  

2

I

+  

1−iodoethane

ICH  

2

CH  

3

 

 

Na

−2NaI

 

Butane

CH  

3

CH  

2

CH  

2

CH  

3

 

 

1−iodoethane

CH  

3

CH  

2

I

+  

1−iodopropane

ICH  

2

CH  

2

CH  

3

 

 

Na

−2NaI

 

Pentane

CH  

3

CH  

2

CH  

2

CH  

2

CH  

3

 

 

1−iodopropane

CH  

3

CH  

2

CH  

2

I

+  

1−iodopropane

ICH  

2

CH  

2

CH  

3

 

 

Na

−2NaI

 

Hexane

CH  

3

CH  

2

CH  

2

CH  

2

CH  

2

CH  

3

 

 

Solve any question of Hydrocarbons with:-Correct option is

D

Butane + Pentane + Hexane

In Wurtz reaction, if two different alkyl halides are treated with sodium metal in presence of dry ether then a mixture of three different products is obtained.

Thus, when a mixture of 1-iodoethane and 1-iodopropane is treated with sodium metal and dry ether, butane, pentane, and hexane will be obtained.

1−iodoethane

CH  

3

CH  

2

I

+  

1−iodoethane

ICH  

2

CH  

3

 

 

Na

−2NaI

 

Butane

CH  

3

CH  

2

CH  

2

CH  

3

 

 

1−iodoethane

CH  

3

CH  

2

I

+  

1−iodopropane

ICH  

2

CH  

2

CH  

3

 

 

Na

−2NaI

 

Pentane

CH  

3

CH  

2

CH  

2

CH  

2

CH  

3

 

 

1−iodopropane

CH  

3

CH  

2

CH  

2

I

+  

1−iodopropane

ICH  

2

CH  

2

CH  

3

 

 

Na

−2NaI

 

Hexane

CH  

3

CH  

2

CH  

2

CH  

2

CH  

2

CH  

3

 

 

Solve any question of Hydrocarbons with:-

Answered by DRAGON94
0

Answer:

Butane + Pentane + Hexane

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