Question

C6029 In the above poble Two masses 40kg and 30kg are connected by a weightless string passing over a frictionless pulley as shown in the following figure. The tension in the string will be:A) 188N B)900/7N C) 288N D)1200/7N​

Answer 1

For m

1

m

1

gsinθ−T=m

1

a

And for m

2

T−m

2

gsinθ=m

2

a

Adding the above equations-

(m

1

−m

2

)gsinθ=(m

1

+m

2

)a

⟹a=

m

1

+m

2

(m

1

−m

2

)gsinθ

⟹a=

60

20×9.8×0.5

=1.63m/s

2

T=m

2

gsinθ+m

2

a=20×9.8×0.5+20×1.63

⟹T=130.66N

Answer:

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