Question

C6H12 (A) has two types of alkanes that can be reduced to one type of C6H14 (B) (B)?

Answer 1

Explanation:

this is the answer for this question

Answer 2

Question: C6H12 (A) has only two types of alkenes that can be reduced to only one type of alkane C6H14 (B)?

Answer:

(A) : $C_{6} H_{12}$ : $2,3-dimethylbut-1-ene$ and $2,3-dimethylbut-2-ene$

(B) : $C_{6} H_{14}$ : $2,3-dimethylbutane$

Explanation:

• Hydrogenation is the process which involves the addition of a hydrogen molecule to the double bond of alkenes resulting in alkane molecules.
• Each carbon atom in alkene binds with one hydrogen atom during the reaction of alkenes with hydrogen gas in the presence of various metal catalysts.
• Since catalysts are required for hydrogenation, the process is often referred to as catalytic hydrogenation. Nickel, Platinum and palladium are the metal catalysts that are frequently used.
• $C_{6}H_{12}$ (A) exist in two types of alkene molecules: $2,3-dimethylbut-1-ene$ and $2,3-dimethylbut-2-ene$  
• These alkene molecules on hydrogenation in presence of $H_{2} /Ni$ gives $C_{6} H_{14}$ alkane (B) which is $2,3-dimethylbutane$.

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