Question

State the expression for frequency of revolution of bob of a conical pendulum​

Answer 1

Answer:

Let's use Newton's second law (ΣF = ma) to derive an expression for: the angle θ in terms of the tangential velocity of the mass, the radius of the circular path (r) and the acceleration due to gravity (g) the height of the conical pendulum in terms of ω2 and g.

Answer 2

Frequency of revolution of bob of a conical pendulum,

F= √[g/(Lcosθ)]

• Conical Pendulum:  It consists of a bob or any weight fixed at one end of the string and the other end is left free. It is almost similar to a simple pendulum. In a conical pendulum, the bob moves in a circular motion with constant speed which gives us traces of a cone.

• The time period of the conical pendulum is given by,                            T = √[Lcosθ]/g)
• Frequency = 1/T, therefore we get the frequency of conical pendulum as F = √[g/(Lcosθ)].