C₆H₅ -CH = CHCHO□(→┴X)C₆H₅CH = CHCH₂OH . In
the above sequence X can be
(a) H₂ / Ni (b) NaBH₄
(c) K₂Cr₂O₇ /H⁺ (d) Both (a) and (b)
Answers
Answered by
0
Explanation:
I think the correct answer is (d)
Answered by
1
NaBH₄ is the reagent needed.
Explanation:
- The carboxylic acid is the maximum organically oxidised form of carbon.
- To reduce it, stronger oxidising agents are needed.
- Only LiBH₄ and NaBH₄ can reduce carboxylic acid into alcohols.
- NaBH₄ at first dissociates into NaH and BH3.
- The BH3 attacks the carboxylic oxygen of acid and forms a complex ion.
- This complex is attacked by NaH which then forms the alcohol and BH3.
- So NaBH₄ is required to reduce the carboxylic acid into alcohol.
- But these reagents don't attack the double bonds.
For more information about NaBH₄,
https://brainly.in/question/15421104
Phenylmethyl ketone can be converted into ethylbenzene in
one step by which of the following reagents?
(a) LiAlH₄ (b) Zn-Hg/HCl
(c) NaBH₄ (d) CH₃MgI
https://brainly.in/question/9177634
NaBH4+ I2 gives? complete the reaction
Similar questions