Question

Which is the correct increasing order of boiling points of
the following compounds?
1 - iodobutane, 1 - bromobutane, 1 - chlorobutane, Butane
(a) Butane < 1-chlorobutane < 1- bromobutane <
1 - iodobutabe
(b) 1 - iodobutane < 1 - bromobutane < 1 - chloroubutane
< Butane
(c) Butane < 1 - iodobutane < 1 - bromobutane <
1 - chlorobutane
(d) Butane < 1 - chlorobutane < 1 - iodobutane <
1 - bromobutane

Answer 1

Explanation:

I think the correct answer is (b)

Answer 2

Butane < 1-chlorobutane < 1 bromobutane  < 1 - iodobutane is the correct order of the boiling points. 1 bromobutane  < 1 - iodobutane is the correct order of the boiling points.

Explanation:

• The variation in boiling points of these four compounds are simply because of their molecular mass.

• The boiling points of the alkyl halides mainly depend on their molecular mass and size of halogen attached.

• This factors make them have more boiling point than their parent atom.

• So, butane has the lowest boiling point of them all.

• Thus, the variation of their boiling point will be like RI > RBr > RCl > RF mainly because of the van der Waal's force of attraction which increases with increase in molecular mass.

For more information about boiling points of alkyl halides,

https://brainly.in/question/1276336

Why alkyl halides have higher boiling points than corresponding hydrocarbons?

https://brainly.in/question/7062404

why alkyl halides have lower boiling point than alcohols - Brainly.in