Question

X is identified as
(a) 2, 4, 6-tribromophenol
(b) 2-bromo-4-hydroxylbenzene sulphonic acid
(c) 3, 5-dibromo-4-hydroxybenzene sulphonic acid
(d) 2-bromophenol

Answer 1

Explanation:

Hydroxylammonium sulfate (NH3OH)2SO4, is the sulfuric acid salt of hydroxylamine. It is primarily used as an easily handled form of hydroxylamine, which is explosive when pure.

Other cations: Ammonium sulfate; Hydrazinium sulfate

Answer 2

2, 4, 6-tribromophenol is the compound.

Explanation:

• The reactant is the 4 hydroxy benzene sulphonic acid.

• The reagent is the excess bromine in water.

• Due to hydrolytic cleavage of bromine, the ions generated are Br+ anr Br-.

• The Br + can act as the electrophile because it's more unstable.

• In the benzene ring, theres hydroxide group which is electron donating group and ring activator.

• While the Sulphonic acid group is a electron pulling group, thereby a ring deactivator.

• So, the substitution will occur at ortho and para positions of hydroxy group.

• Now, due to excess bromine, the Sulphonic acid is also substituted by bromine.

• So the product formed is  2, 4, 6-tribromophenol.

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