Question

C6h6+cl2−→−−−−uv light product. in above reaction product is

Answer 1

chlorobenzene (C6H5Cl)
Hope this can help you

Answer 2

Explanation:

When chlorine or halogen reacts in the presence of UV light then the reaction takes place in three steps. These steps are as follows.

• Initiation

$Cl_{2} + UV light \rightarrow 2Cl \cdot$

• Propagation

$Cl\cdot + C_{6}H_{6} \rightarrow C_{6}H_{5}\cdot + HCl$

• Termination

$C_{6}H_{5}\cdot + Cl_{2} \rightarrow C_{6}H_{5}Cl + Cl·$

Therefore, we can conclude that product in the reaction is $C_{6}H_{6} + Cl_{2} \overset{UV light}{\rightarrow} C_{6}H_{5}Cl$