Question

CaCl, CO, and H, O are produced by the reaction of light HCI with CaCO. How many grams of HCl will be required to produce 50g CaCO to 55.5g CaCl, 22g CO, and 9g H, O? What is the required number of mail for HCl?​

Answer 1

Explanation:

The mass of HCl is

1000

0.75×36.5

×

25=

0.684g

.

1 mole of calcium carbonate reacts with 2 moles of HCl.

Hence, the mass of calcium carbonate that will react completely with 0.684 g of HCl is

2×36.5

100

×

0.684=

0.937g