Question

CaCo3 decmposes to give CaO and CO2 if the masses of CaO and CO2 produced are 5.6 g and 4.4 g respectively by heating 12 g of an impure CaCO3 sample then the %of imprity sample will be​

Answer 1

9) Mass of reactant, CaCO 3 (impure) = 12 g

Mass of Products:

CaO = 5.6 g

CO2 = 4.4 g

According to the Law of Conservation of Mass -

Mass of Reactants = Mass of Products

So,

CaCO 3 = CaO + CO2

12 g = (5.6 + 4.4) g

But, 12 g ≠10 g

Therefore, the % Purity of the sample = (10 g12 g) x 100

= 0.83333 x 100 = 83.33%

Thus, the % Impurity of the sample = (100 - 83.33)% = 16.67%

So, the correct option should be (2).

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