Physics, asked by jaldasathyam2847, 3 months ago

caco3+ hcl cacl2+co2+ h2o 100 gm of caco3 produces 44 gm of co2 how much amount of co2 is produced when 300 gm of caco3 is used​

Answers

Answered by swety38
0

Answer:

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Answered by nisha02345
0

Answer:

CaCO3 + 2HCl -----> CaCl2 + H2O + CO2.

2.5g? g

Mass of CaCO3= 40+12+3(16)=52+ 48= 100.

Molar mass of CaCO3=100g.

Mass of CaCl2= 40 + 2(35.5)= 40+ 71= 111.

Molar mass of CaCl2=111g.

Mass of CaCO3 (g) Mass of CaCl2 (g)

For 100g of CaCO

3

, 111g of CaCl_2$$ is formed.

let for 2.5g of CaCO

3

, x g of CaCl

2

is formed.

Thus, by cross multiplication,

x=111×2.5/100=2.775g=2.78g.

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