Question

calaculte the pysical address given the following 8086 register contents:
(1) SS=7698h
SP= 01FFh
(2) CS= 5526h
IP= 8874h
​

Answer 1

Answer:

2nd one is the answer but i don't know the reason

Answer 2

Physical address given the following 8086 register contents are

76B7F  and  5DAD4

According to question,

The value of the stack segment register (SS) = 7698h

The value which is Offset i.e, stack pointer (SP) = 01FFh

Thus, Physical address of the top of the stack is given by,

7 6 9 8 0

+ 0 1 F F

7 6 B 7 F

The value of the stack segment register (CS) = 5526h

The value which is Offset i.e, stack pointer (IP) = 8874h

Thus, Physical address of the top of the stack is given by,

5 5 2 6 0

+ 8 8 7 4

5 D A D 4