Question

Calchlate the area of the triangle with sides8 cm,15 cm,17cm

Answer 1

Answer :


$given \: sides \: of \: triangle \: = 8cm \ \: \: 15cm \: \: 17cm \\ \\ = > \: when \: the \: sides \: of \: triangle \: are \: given \: then \\ \\ area \: of \: triangle \: = \: \sqrt{s(s - a)(s - b)(s - c)} \\ \\ where \: s \: is \: semiperimeter \: and \: a \: b \: c \: are \: sides \\ \\ \\ = > \: let \: 8cm \: = \: a \\ \\ = > \: 15cm \: = \: b \\ \\ = > \: 17 \: cm \: = \: c \\ \\ = > \: semiperimeter \: (s) \: = \: \frac{a + b + c}{2} \\ \\ = > \: s \: = \frac{8 + 15 + 17}{2} \\ \\ = > \: s \: = \: \frac{40}{2} \\ \\ = > \: s \: = 20 \\ \\ = > \: now \: area \: = \: \sqrt{20(20 - 8)(20 - 15)(20 - 17)} \\ \\ = > \: \sqrt{20 \times 12 \times 5 \times 3} \\ \\ = > \: \sqrt{3600} \\ \\ = > \: \sqrt{60 \times 60} \\ \\ = > \: 60 \\ \\ \\ therefore \: area \: of \: triangle \: = \: 60 \: cm {}^{2}$



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