Question

Calcium carbonate is a common ingredient in stomach antacids. If one antacid tablet has 60 mg of
CaCO3, how many moles of CaCO3 are there in 200 tablets.

Answer 1

Answer:

0.12

Explanation:

In order we first need to find out the number of moles present in one tablet of CaCO3.

We are given that one tablet contains 60mg of CaCO3. 60 mg is equivalent to  0.06 grams.

Molar mass of CaCO3 = 100 g/mol

So one tablet has = 0.06/100 = 0.0006 moles

200 tablets will have = 200 x 0.0006 = 0.12 moles of CaCO3

Answer 2

Given - Amount of CaCO3 = 60 mg

Total tablets - 200

Find - Moles of CaCO3 in 200 tablets.

Solution - The molar mass of CaCO3 is 100 gram/mole.

Now, amount of CaCO3 in one antacid tablets is 60 mg. Converting it into grams, 60 mg = 0.06 grams.

So, 1 tablet has 0.06 gram of CaCO3

200 tablets will have = 0.06*200

200 tablets will have CaCO3 = 12 grams

Hence, calculating number of moles = mass/molar mass

Number of moles = 12/100

Number of moles = 0.12

Moles of CaCO3 present in 200 tablets are 0.12.