Question

Calcium carbonate reacts with aqueous hydrochloric acid according to the reaction given below:
CaCO3 (s) +HCl (aq) -->CaCl2 (aq)+ H2O (l)+ CO2 (g)
What mass of calcium carbonate is required to react completely with 25 ml of 0.75 M HCl solution?

Answer 1

Answer:

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Explanation:

The mass of HCl is

1000

0.75×36.5

×25=0.684g.

1 mole of calcium carbonate reacts with 2 moles of HCl.

Hence, the mass of calcium carbonate that will react completely with 0.684 g of HCl is

2×36.5

100

×0.684=0.937g