Question

Calclute the molecular mass of A.Mg3 N2 B.(NH4)2 co3

Answer 1

Explanation:

Molecular mass of Mg=24

Molecular mass of N =14

so molecular formula of Mg3N2

= 24×3+14×2

=72+28

=100

Molecular mass og N=14

molecular mass of H=1

molecular mass of C=12

molecular mass of O=16

so molecular mass of (NH4)2CO3

= 14×2+4×2+12+16×3

=28+8+12+48

=96

Answer 2

Hey mate

Here's your Answer

A.Mg3N2

Molar masses Individually_

Mg=25u

Mg3=25*3

=75u

N=14

N2=28u

therefore

Mg3N2=75+28=103g

B.(NH4)2CO3

Molar masses individually_

N=14u

H=1u

H4=4u

C=12u

O=16u

O3=48u

Therefore

(NH4)2CO3

=(14+4)2+12+48

=96g

Thank you

Regards☺